X^2-2x-5040=0

Solution for X^2-2x-5040=0 equation:

X^2-2X-5040=0

a = 1; b = -2; c = -5040;
Δ = b2-4ac
Δ = -22-4·1·(-5040)
Δ = 20164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20164}=142$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-142}{2*1}=\frac{-140}{2}
=-70
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+142}{2*1}=\frac{144}{2}
=72
$